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	<title>Comments on: 1000 movies in 23 years</title>
	<link>http://pxl9.com/k/blog/1000-movies-in-23-years/</link>
	<description>taglines don't reveal much</description>
	<pubDate>Tue, 06 Jan 2009 02:17:53 +0000</pubDate>
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		<title>by: nicolas zein</title>
		<link>http://pxl9.com/k/blog/1000-movies-in-23-years/#comment-921</link>
		<pubDate>Mon, 30 Apr 2007 06:24:57 +0000</pubDate>
		<guid>http://pxl9.com/k/blog/1000-movies-in-23-years/#comment-921</guid>
					<description>hey bro, i never told you but this thing is tight. Good work. Love you man, come down soon you punk!!</description>
		<content:encoded><![CDATA[<p>hey bro, i never told you but this thing is tight. Good work. Love you man, come down soon you punk!!
</p>
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		<title>by: kevint</title>
		<link>http://pxl9.com/k/blog/1000-movies-in-23-years/#comment-36</link>
		<pubDate>Mon, 19 Feb 2007 18:03:47 +0000</pubDate>
		<guid>http://pxl9.com/k/blog/1000-movies-in-23-years/#comment-36</guid>
					<description>If you write your own list we can write a SQL query that finds the distinct elements...</description>
		<content:encoded><![CDATA[<p>If you write your own list we can write a SQL query that finds the distinct elements&#8230;
</p>
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		<title>by: Vesal</title>
		<link>http://pxl9.com/k/blog/1000-movies-in-23-years/#comment-35</link>
		<pubDate>Mon, 19 Feb 2007 17:57:55 +0000</pubDate>
		<guid>http://pxl9.com/k/blog/1000-movies-in-23-years/#comment-35</guid>
					<description>How 'bout you make a list of movies you've seen that Vesal hasn't seen? =D That would really help me.</description>
		<content:encoded><![CDATA[<p>How &#8217;bout you make a list of movies you&#8217;ve seen that Vesal hasn&#8217;t seen? =D That would really help me.
</p>
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		<title>by: John A.</title>
		<link>http://pxl9.com/k/blog/1000-movies-in-23-years/#comment-14</link>
		<pubDate>Thu, 04 Jan 2007 11:59:21 +0000</pubDate>
		<guid>http://pxl9.com/k/blog/1000-movies-in-23-years/#comment-14</guid>
					<description>1000 movies * 90 minutes each (avg) = 90000 minutes = 1500 hours = exacly 62.5 days woooooooooow. Thats about as long as I've been here.</description>
		<content:encoded><![CDATA[<p>1000 movies * 90 minutes each (avg) = 90000 minutes = 1500 hours = exacly 62.5 days woooooooooow. Thats about as long as I&#8217;ve been here.
</p>
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